The Elements of Euclid: In which the Propositions are Demonstrated in a New and Shorter Manner Than in Former Translations, and the Arrangement of Many of Them Altered, to which are Annexed Plain and Spherical Trigonometry, Tables of Logarithms from 1 to 10,000, and Tables of Sines, Tangents, and Secants, Natural and Artificialauthor, and sold, 1776 - 264 sider |
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Resultater 1-5 af 8
Side 21
... EFGH , be conftitute upon the equal bafes BC , FG , and between the fame parallels AH , BG ; the parallelogram ABCD will be equal to EFGH , Ax . 7 . For , join EB , CH , the parallelograms AC , EG * , are each equal to the parallelogram ...
... EFGH , be conftitute upon the equal bafes BC , FG , and between the fame parallels AH , BG ; the parallelogram ABCD will be equal to EFGH , Ax . 7 . For , join EB , CH , the parallelograms AC , EG * , are each equal to the parallelogram ...
Side 110
... EFGH , whofe common fections are EF , GH ; then EF is parallel to GH : For , if EF , GH , are not parallel , if produced , they will meet , either toward F , H , or E , G. Let them meet in K : Then , because EFK is in the plain AB , all ...
... EFGH , whofe common fections are EF , GH ; then EF is parallel to GH : For , if EF , GH , are not parallel , if produced , they will meet , either toward F , H , or E , G. Let them meet in K : Then , because EFK is in the plain AB , all ...
Side 131
... EFGH . If not , the circle ABCD will be to fome figure either lefs or greater than the circle EFGH . First , let it be to a figure S , lefs than the circle EFGH , in which infcribe the fquare EFGH , which will be greater than half the ...
... EFGH . If not , the circle ABCD will be to fome figure either lefs or greater than the circle EFGH . First , let it be to a figure S , lefs than the circle EFGH , in which infcribe the fquare EFGH , which will be greater than half the ...
Side 132
... EFGH exceeds the figure S6 . Let thefe be the fegments cut off by the right lines EK , KF , FL , LG , GM , MH , HN ... EFGH . In like manner , it is proved that the fquare of FH to the fquare of BD is not to the circle EFGH as fome ...
... EFGH exceeds the figure S6 . Let thefe be the fegments cut off by the right lines EK , KF , FL , LG , GM , MH , HN ... EFGH . In like manner , it is proved that the fquare of FH to the fquare of BD is not to the circle EFGH as fome ...
Side 139
... EFGH , fo is the cone AL to the cone EN . If not , the circle ABCD is to the circle EFGH , as the cone AL is to fome folid greater or less than the cone EN . First , let it be to a folid X lefs than the cone ; and let the folid I be ...
... EFGH , fo is the cone AL to the cone EN . If not , the circle ABCD is to the circle EFGH , as the cone AL is to fome folid greater or less than the cone EN . First , let it be to a folid X lefs than the cone ; and let the folid I be ...
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The Elements of Euclid: In Which the Propositions Are Demonstrated in a New ... Euclid Ingen forhåndsvisning - 2015 |
Almindelige termer og sætninger
ABCM angle ABC angle BAC arch bafe bafe BC baſe becauſe bifected Book XI circle ABCD circle EFGH circumference cofine common fection cone contained cylinder defcribe DEFH diameter draw drawn equal angles equal to AC equiangular equilateral equimultiples fame altitude fame multiple fame plain fame proportion fame reaſon fecond fegment femicircle fhall fides fimilar folid angle folid parallelopipedons fome fore fphere fquare of AC fubtending given right line greater infcribed join lefs leſs likewife magnitudes parallel parallelogram perpendicular plain paffing polygon polyhedron prifms PROP pyramid rectangle right angles right line AB right lined figure Secant Sine Tang tangent thefe THEOR theſe triangle ABC triplicate ratio Wherefore whofe bafe whoſe
Populære passager
Side 80 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Side 72 - F, equal to them in number, be taken two and two in the fame ratio, and if their analogy be perturbate, viz. as A is to B, fo is E to F, and B to C as D to E ; and if the firft A be greater than the third C, then the fourth D will be greater than the fixth F ; if equal, equal ; and, if lefs, lefs.
Side 91 - BAC was proved to be equal to ACD : Therefore the whole angle ACE is equal to the two angles ABC, BAC...
Side x - If a straight line meets two straight lines, so as to make the two interior angles on the same side of it taken together less than two right angles, these straight lines being continually produced, shall at length meet upon that side on which are the angles which are less than two right angles.
Side 54 - Let ABC be the given circle, and D the given straight line, not greater than the diameter of the circle. It is required to place in the circle ABC a straight line equal to D.
Side 9 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz.
Side 13 - From this it is manifest that if one angle of a triangle be equal to the other two it is a right angle, because the angle adjacent to it is equal to the same two ; (i.
Side 69 - Let AB be the fame multiple of C, that DE is of F : C is to F, as AB to DE. Becaufe AB is the fame multiple of C that DE is of F ; there are as many magnitudes in AB equal to C, as there are in...
Side 91 - BGC: for the same reason, whatever multiple the circumference EN is of the circumference EF, the same multiple is the angle EHN of the angle EHF: and if the circumference BL be equal to the circumference EN, the angle BGL is also equal to the angle EHN ; (in.
Side 80 - ... reciprocally proportional, are equal to one another. Let AB, BC be equal parallelograms which have the angles at B equal, and let the sides DB, BE be placed in the same straight line ; wherefore also FB, BG are in one straight line (2.