 | 1811 - 572 sider
...have Sin. A. Cos. B + Cos. A. Sin. B — t- ' and Sin.c = Sin.(180* — A + B) = Sin. A + B, since the sine of an angle is equal to the sine of its supplement. Hence Sin. A + B = Sin. A. Cos. B 4- Cos. A. Sin. BQED All this is perfectly legitimate ; but how is... | |
 | Miles Bland - 1819 - 442 sider
...be found from the tables ; and (78) A e CB : CA :: sin. A : sin. B•, CA hence sin. B = ~ x sin. A, and may .-. be determined. But as the sine of an angle...the angle B*. The angle B being found, the angle C= 1 8O - (A + B), and may .-. be determined. Also sin. A : sin. C :: CB : BA, whence BA = CB x •. -... | |
 | Robert Gibson - 1821 - 594 sider
...when the given angle is acute and opposite the lesser of the given sides, the answer is ambiguous, as the sine of an angle is equal to the .sine of its supplement, consequently the required angle opposite that other given side may be obtuse, or acute ; unless it... | |
 | Ferdinand Rudolph Hassler - 1826 - 640 sider
...No. 1, of the series A, or first definition, we have in the two triangles, and in both cases, (since the sine of an angle is equal to the sine of its supplement.) dd — = sin C ; and — = sin B bc Therefore : d = b . sin C = c . sin B Or, expressed in a proportion... | |
 | Ferdinand Rudolph Hassler - 1826 - 208 sider
...No. l, of the series A, or first definition, we have in the two triangles, and in both cases, (since the sine of an angle is equal to the sine of its supplement.) dd — = sin С ; and — = sin В b Therefore : d = i . sin С = с . ein B Or, expressed in a proportion... | |
 | Robert Gibson - 1832 - 290 sider
...but when the given angle is acute, and opposite the less of the given sides,the answer is ambiguous, as the sine of an angle is equal to the sine of its supplement, consequently the required angle opposite that other given side may be obtuse or acute, unless if is... | |
 | Henry Pearson - 1833 - 164 sider
...angle is equal to the sine of its complement. C 7. Sin (TT - 9) = sin 9, cos (TT - 9) = - cos Q. Or the sine of an angle is equal to the sine of its supplement, and the cosine of an angle is equal to the cosine of its supplement, with its algebraical sign changed.... | |
 | John Charles Snowball - 1837 - 322 sider
...determine B from (ii), С and с are known from (i) and (iii), and the triangle is determined. Now the sine of an angle is equal to the sine of its supplement, and therefore there are two angles which satisfy (ii), the one greater and the other less than 90°.... | |
 | Robert Gibson, James Ryan - 1839 - 452 sider
...but when the given angle is acute, and opposite the less of the given sides, the answer is ambiguous, as the sine of an angle is equal to the sine of ita supplement, consequently the required angle opposite that other given side may be obtuse or acute,... | |
 | Nathan Scholfield - 1845 - 894 sider
...^ = — that is, sin. d=sin. (180° — 0) an important proposition which enunciated in words, is, the sine of an angle is equal to the sine of its supplement. Again, cs_cs; CA~CA cos. 6=— cos. (180°— 0), 42 If, as in the annexed figure, we draw CP', making... | |
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The sine of an angle is equal to the sine of its supplement. The sine rule Consider fig. 
