The school Euclid: comprising the first four books, by A.K. Isbister1862 |
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Side 59
... Gnomon . A E D F H K B G C ' Thus the parallelogram HG , together with the complements AF , FC , is the Gnomon , which is more briefly expressed by the letters AGK , or EHC , which are at the opposite angles of the parallelograms which ...
... Gnomon . A E D F H K B G C ' Thus the parallelogram HG , together with the complements AF , FC , is the Gnomon , which is more briefly expressed by the letters AGK , or EHC , which are at the opposite angles of the parallelograms which ...
Side 65
... gnomon CMG ; therefore the gnomon CMG is equal to the rectangle AD , DB ; ( ax . 1 ) to each of these equals add LG , which is equal to the square of CD , ( 11. 4 , Cor . ) since CD is equal to LH ; therefore the gnomon CMG , together ...
... gnomon CMG ; therefore the gnomon CMG is equal to the rectangle AD , DB ; ( ax . 1 ) to each of these equals add LG , which is equal to the square of CD , ( 11. 4 , Cor . ) since CD is equal to LH ; therefore the gnomon CMG , together ...
Side 66
... gnomon CMG . But AM is the rectangle contained by AD , DB , since DM is equal to DB ; ( 11. 4 , Cor . ) therefore the gnomon CMG is equal to the rectangle AD , DB ; add to each of these LG , which is equal to the square of CB ...
... gnomon CMG . But AM is the rectangle contained by AD , DB , since DM is equal to DB ; ( 11. 4 , Cor . ) therefore the gnomon CMG is equal to the rectangle AD , DB ; add to each of these LG , which is equal to the square of CB ...
Side 67
... gnomon AKF , together with the square CK , therefore the gnomon AKF , together with the square CK , is double of AK ; but twice the rectangle AB , BC , is double of AK , for BK is equal to BC ; ( II . 4 , Cor . ) therefore the gnomon ...
... gnomon AKF , together with the square CK , therefore the gnomon AKF , together with the square CK , is double of AK ; but twice the rectangle AB , BC , is double of AK , for BK is equal to BC ; ( II . 4 , Cor . ) therefore the gnomon ...
Side 69
... gnomon AOH was demonstrated to be quadruple of AK ; therefore four times the rectangle AB , BC , is equal to the gnomon АОН ; to each of these add XH , which is equal to the square of AC ; ( 11.4 , Cor . ) therefore four times the ...
... gnomon AOH was demonstrated to be quadruple of AK ; therefore four times the rectangle AB , BC , is equal to the gnomon АОН ; to each of these add XH , which is equal to the square of AC ; ( 11.4 , Cor . ) therefore four times the ...
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The School Euclid: Comprising the First Four Books, Chiefly from the Text of ... A. K. Isbister Ingen forhåndsvisning - 2009 |
Almindelige termer og sætninger
AB is equal adjacent angles alternate angles angle ABC angle AGH angle BAC angle BCD angle EAB angle EDF angle equal angles CBA base BC BC is equal circle ABC constr DEMONSTRATION describe the circle diameter double equal angles equal straight lines equal to BC equilateral and equiangular exterior angle given circle given rectilineal angle given straight line gnomon greater inscribed interior and opposite less Let ABC Let the straight opposite angles parallel to CD parallelogram pentagon perpendicular Q. E. D. PROP rectangle AE rectangle contained rectilineal figure References Prop References-Prop remaining angle required to describe right angles segment semicircle side BC square of AC straight line AB straight line AC THEOREM touches the circle triangle ABC triangle DEF twice the rectangle
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Side 141 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal...
Side 35 - If a side of any triangle be produced, the exterior angle is equal to the two interior and opposite angles ; and the three interior angles of every triangle are equal to two right angles.
Side 71 - In obtuse-angled triangles, if a perpendicular be drawn from either of the acute angles to the opposite side produced, the square of the side subtending the obtuse angle, is greater than the squares of the sides containing the obtuse angle, by twice the rectangle contained by the side upon which, when produced, the perpendicular falls, and the straight line intercepted without the triangle, between the perpendicular and the obtuse angle. Let ABC be an obtuse-angled triangle, having the obtuse angle...
Side 33 - That, if a straight line falling on two straight lines make the interior angles on the same side less than two right angles, the two straight lines, if produced indefinitely, meet on that side on which are the angles less than the two right angles.
Side 61 - If a straight line be bisected and produced to any point, the rectangle contained by the whole line thus produced and the part of it produced, together with the square of...
Side 43 - Triangles upon equal bases, and between the same parallels, are equal to one another.
Side 27 - ... shall be greater than the base of the other. Let ABC, DEF be two triangles, which have the two sides AB, AC, equal to the two DE, DF, each to each, viz.
Side 77 - An angle in a segment is the angle contained by two straight lines drawn from any point in the circumference of the segment to the extremities of the straight line which is the base of the segment.
Side 15 - The angles which one straight line makes with another upon one side of it, are either two right angles, or are together equal to two right angles.