Solutions of the problems and riders proposed in the Senate-house examination for 1854, by the moderators and examiners |
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Resultater 1-5 af 28
Side 7
... points A and B successively , the angle between the two positions of BC is tan 18 . -1 Let EF , fig . ( 6 ) , be drawn parallel to BA , through E the middle point of BC . Then , if G be the centre of gravity of the piece of wire , EG ...
... points A and B successively , the angle between the two positions of BC is tan 18 . -1 Let EF , fig . ( 6 ) , be drawn parallel to BA , through E the middle point of BC . Then , if G be the centre of gravity of the piece of wire , EG ...
Side 7
... points A and B successively , the angle between the two positions of BC is tan118 . Let EF , fig . ( 6 ) , be drawn parallel to BA , through E the middle point of BC . Then , if G be the centre of gravity of the piece of wire , EG ...
... points A and B successively , the angle between the two positions of BC is tan118 . Let EF , fig . ( 6 ) , be drawn parallel to BA , through E the middle point of BC . Then , if G be the centre of gravity of the piece of wire , EG ...
Side 20
... middle point of the given chord ; then the equation to the circle may be written x2 + y2 — 2ax — 2by + f = 0 , and the equations to the chords will be X α 20 [ Jan. 17 , SENATE - HOUSE PROPLEMS AND RIDERS .
... middle point of the given chord ; then the equation to the circle may be written x2 + y2 — 2ax — 2by + f = 0 , and the equations to the chords will be X α 20 [ Jan. 17 , SENATE - HOUSE PROPLEMS AND RIDERS .
Side 28
... middle point of GG2 , and since G2 is fixed the locus of G will be similar to the locus of G1 , and of half the linear mag- nitude : also when PCQ is a straight line , G will be at C. 1 To find the locus of G. Join UV the middle points ...
... middle point of GG2 , and since G2 is fixed the locus of G will be similar to the locus of G1 , and of half the linear mag- nitude : also when PCQ is a straight line , G will be at C. 1 To find the locus of G. Join UV the middle points ...
Side 35
... middle points of the sides AB , AD , the part EGHF is one - fourth of the perimeter of the elastic tube . Also the free portion GH is circular : for the pressure and tension being the same at every point , the radius also must be the ...
... middle points of the sides AB , AD , the part EGHF is one - fourth of the perimeter of the elastic tube . Also the free portion GH is circular : for the pressure and tension being the same at every point , the radius also must be the ...
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Solutions of the Problems and Riders Proposed in the Senate-House ... Exam Papers Cambridge Univ Ingen forhåndsvisning - 2016 |
Almindelige termer og sætninger
angular velocity asymptote axes Cambridge catenary centre of force centre of gravity chord circle cloth conic section constant cos² cose cosẞ cota cotß Crown 8vo curvature curve cylinder denoting described diameter direction distance dx dy dy dx ecliptic elastic ellipse equal equation equilibrium Fellow of St fixed point fluid geometrical progression given Hence horizontal hyperbola inclined plane intersection lamina latus rectum length locus longitude M.A. Fellow major axis middle point motion orbit parabola parallel particle passing perpendicular position pressure projection prove radius refraction right angles ring shew sides Similarly sine sino sinẞ straight line string Supposing surface tana tangent tanß triangle Trinity College tube V₁ vertical
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