Geometrical problems deducible from the first six books of Euclid, arranged and solved. To which is added, an appendix containing the elements of plane trigonometryJ. Smith, Printer to the University; and sold by Nicholson & Son, Deighton & Sons, Thorpe, and Newby, Cambridge; and J. Mawman, and F. C. & J. Rivington, London., 1819 - 377 sider |
Fra bogen
Resultater 1-5 af 100
Side 10
Miles Bland. ( 16. ) To trisect a right angle . Let ACB be a right angle . In CA take any point A , and on CA ... ABC ; bisect the angles CAB , CBA by the lines AD , BD meeting in D , and draw DE , DF parallel to CA and CB respectively ...
Miles Bland. ( 16. ) To trisect a right angle . Let ACB be a right angle . In CA take any point A , and on CA ... ABC ; bisect the angles CAB , CBA by the lines AD , BD meeting in D , and draw DE , DF parallel to CA and CB respectively ...
Side 13
... angles at G are right angles , therefore the angle DCG GCE , and FCB is bisected by CG . = ( 21. ) If a straight ... ABC be bi- E sected by the line BD , and through any point D in this line draw GDFE meeting the sides in G and F , and ...
... angles at G are right angles , therefore the angle DCG GCE , and FCB is bisected by CG . = ( 21. ) If a straight ... ABC be bi- E sected by the line BD , and through any point D in this line draw GDFE meeting the sides in G and F , and ...
Side 26
... ABC , ABD cut each other in A and B , draw the diameters AC , AD , and join BC , BD ; CB and BD are in the same straight line . Join AB ; the angles ABC , ABD being angles in semicircles are right angles , and therefore ( Eucl . i . 13 ...
... ABC , ABD cut each other in A and B , draw the diameters AC , AD , and join BC , BD ; CB and BD are in the same straight line . Join AB ; the angles ABC , ABD being angles in semicircles are right angles , and therefore ( Eucl . i . 13 ...
Side 37
... angle equal to the given angle , and make OE equal to the given line . From E draw EF , to the circle CFD , equal to ... ABC ; the angle of inclination is equal to half the angle at the centre standing on an arc equal to the sum of CA ...
... angle equal to the given angle , and make OE equal to the given line . From E draw EF , to the circle CFD , equal to ... ABC ; the angle of inclination is equal to half the angle at the centre standing on an arc equal to the sum of CA ...
Side 38
... angle COF , which stands on the arc CF equal to CA and BD together . 2. Next , let AB , CD intersect in E , without ... ABC , ADE are equiangular ( Eucl . vi . 7. ) , and 38 [ Sect . 2 . GEOMETRICAL PROBLEMS .
... angle COF , which stands on the arc CF equal to CA and BD together . 2. Next , let AB , CD intersect in E , without ... ABC , ADE are equiangular ( Eucl . vi . 7. ) , and 38 [ Sect . 2 . GEOMETRICAL PROBLEMS .
Indhold
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12 | |
17 | |
19 | |
23 | |
25 | |
30 | |
140 | |
146 | |
147 | |
154 | |
157 | |
158 | |
164 | |
170 | |
36 | |
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52 | |
58 | |
63 | |
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171 | |
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273 | |
295 | |
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Almindelige termer og sætninger
ABCD angle ABC angles at F base centre chord circle ABC circles cut circles touch circumference describe a circle divided draw a line Draw the diameter drawn parallel duplicate ratio equal angles equiangular Eucl extremities given angle given circle given in position given line given point given ratio given square given straight line given triangle intercepted isosceles triangle Join AE Join BD Let AB Let ABC let fall line given line joining line required lines be drawn lines drawn mean proportional opposite side parallel to BC parallelogram pendicular perpen point of bisection point of contact point of intersection point required radius rectangle rectangle contained right angles segments semicircle shewn tangent touches the circle trapezium triangle ABC