Geometrical problems deducible from the first six books of Euclid, arranged and solved. To which is added, an appendix containing the elements of plane trigonometryJ. Smith, Printer to the University; and sold by Nicholson & Son, Deighton & Sons, Thorpe, and Newby, Cambridge; and J. Mawman, and F. C. & J. Rivington, London., 1819 - 377 sider |
Fra bogen
Resultater 1-5 af 100
Side 25
... circumference , making equal angles with the line joining the same point and the centre , the parts of the lines which are intercepted within the circle are equal . From the point P without the circle ABC let two lines PB , PD be drawn ...
... circumference , making equal angles with the line joining the same point and the centre , the parts of the lines which are intercepted within the circle are equal . From the point P without the circle ABC let two lines PB , PD be drawn ...
Side 26
... circle be described on the radius of another circle ; any straight line drawn from the point where they meet , to ... ABC , ABD cut each other in A and B , draw the diameters AC , AD , and join BC , BD ; CB and BD are in the same straight ...
... circle be described on the radius of another circle ; any straight line drawn from the point where they meet , to ... ABC , ABD cut each other in A and B , draw the diameters AC , AD , and join BC , BD ; CB and BD are in the same straight ...
Side 35
... circle ABC ; bisect it in G and join OG ; A E D K H B make OH = OG , and through H , draw IK parallel to AB ; IK is ... circle , to draw a straight line , the part of which intercepted by the circle , shall be equal to a given line , not ...
... circle ABC ; bisect it in G and join OG ; A E D K H B make OH = OG , and through H , draw IK parallel to AB ; IK is ... circle , to draw a straight line , the part of which intercepted by the circle , shall be equal to a given line , not ...
Side 37
... circles may be equal to a given line . Let AB , CD , the bases of the segments be in ... circle CFD , equal to the radius OB ; draw OI pa- rallel to EF ; join IF ... ABC ; the angle of inclination is equal to half the angle at the centre ...
... circles may be equal to a given line . Let AB , CD , the bases of the segments be in ... circle CFD , equal to the radius OB ; draw OI pa- rallel to EF ; join IF ... ABC ; the angle of inclination is equal to half the angle at the centre ...
Side 38
... circle , join CO , FO . Then AB being parallel to FD , ( ii . 1. ) AF is ... circles which do not meet each other , two lines be drawn to their centres , which have the ... ABC , ADE are equiangular ( Eucl . vi . 7. ) , and 38 [ Sect . 2 ...
... circle , join CO , FO . Then AB being parallel to FD , ( ii . 1. ) AF is ... circles which do not meet each other , two lines be drawn to their centres , which have the ... ABC , ADE are equiangular ( Eucl . vi . 7. ) , and 38 [ Sect . 2 ...
Indhold
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12 | |
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19 | |
23 | |
25 | |
30 | |
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36 | |
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Almindelige termer og sætninger
ABCD angle ABC angles at F base centre chord circle ABC circles cut circles touch circumference describe a circle divided draw a line Draw the diameter drawn parallel duplicate ratio equal angles equiangular Eucl extremities given angle given circle given in position given line given point given ratio given square given straight line given triangle intercepted isosceles triangle Join AE Join BD Let AB Let ABC let fall line given line joining line required lines be drawn lines drawn mean proportional opposite side parallel to BC parallelogram pendicular perpen point of bisection point of contact point of intersection point required radius rectangle rectangle contained right angles segments semicircle shewn tangent touches the circle trapezium triangle ABC