Pure mathematics, Bind 11874 |
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Resultater 1-5 af 16
Side 108
... exterior angle shall be greater than either of the interior opposite angles . Let ABC be a triangle , and let its side BC be produced to D. The exterior angle ACD shall be greater than either of the interior opposite angles CBA , BAC ...
... exterior angle shall be greater than either of the interior opposite angles . Let ABC be a triangle , and let its side BC be produced to D. The exterior angle ACD shall be greater than either of the interior opposite angles CBA , BAC ...
Side 109
... angle of the triangle ABC , it is greater than the interior and opposite angle ABC ( I. 16 ) . To each of these add ... exterior angle of the triangle BDC , it is greater than the interior and opposite angle BCD ( I. 16 ) . But the angle ...
... angle of the triangle ABC , it is greater than the interior and opposite angle ABC ( I. 16 ) . To each of these add ... exterior angle of the triangle BDC , it is greater than the interior and opposite angle BCD ( I. 16 ) . But the angle ...
Side 111
... angle . Let ABC be a triangle , and from the points B , C , the ends of the side BC , let the two straight lines BD ... exterior angle of a triangle is greater than the interior and opposite angle ( I. 16 ) , therefore BDC , the exterior ...
... angle . Let ABC be a triangle , and from the points B , C , the ends of the side BC , let the two straight lines BD ... exterior angle of a triangle is greater than the interior and opposite angle ( I. 16 ) , therefore BDC , the exterior ...
Side 117
... angle BHA is equal to the angle EFD ( I. 4 ) . But the angle EFD is equal to the angle BCA ( Hyp . ) ; Therefore the angle BHA is also equal to the angle BCA BCA . ( Ax . 1 ) ; That is , the exterior angle BHA of the triangle AHC , is ...
... angle BHA is equal to the angle EFD ( I. 4 ) . But the angle EFD is equal to the angle BCA ( Hyp . ) ; Therefore the angle BHA is also equal to the angle BCA BCA . ( Ax . 1 ) ; That is , the exterior angle BHA of the triangle AHC , is ...
Side 118
... exterior angle AEF is greater than the interior and opposite angle EFG ( I. 16 ) . But the angle AEF is also equal to EFG ( Hyp . ) , which is impossible ; Therefore AB and CD , being produced , do not meet towards B , D. In like manner ...
... exterior angle AEF is greater than the interior and opposite angle EFG ( I. 16 ) . But the angle AEF is also equal to EFG ( Hyp . ) , which is impossible ; Therefore AB and CD , being produced , do not meet towards B , D. In like manner ...
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a²b a²b² a²x² a³b ab² ab³ ABCD adjacent angles algebraical algebraical quantity angle ABC angle BAC angle BCD angle EDF angle equal base BC BC is equal bisect brackets cent centim centre circle ABC coefficient common Const cube root decimal figures denominator distance divided divisor equation expression exterior angle factor Find the value fraction given rectilineal given straight line greater Hence join kilom Let ABC logarithm metres millig Multiply opposite angles parallel parallelogram perpendicular PROOF.-Because Q. E. D. Proposition quotient ratio rectangle contained remainder right angles segment side BC square on AC square root subtraction term triangle ABC x²y x²y² x³y xy² xy³
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