The Principles of the Solution of the Senate-house 'riders,' Exemplified by the Solution of Those Proposed in the Earlier Parts of the Examinations of the Years 1848-1851Macmillan & Company, 1851 - 116 sider |
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Resultater 1-5 af 11
Side 29
... equations will manifestly be satisfied by supposing Hence Ap + 29 Ap + 3 , & c . ... each = 0 . = We then have 1 = ( p + 1 ) Ap + 1 ; 1 .. Ap + 1 p + 1 A , A 2 + + ... + np N 1 + 2 + ... + n p + 1 and therefore limit 1 +2 + ... tr N2 + ...
... equations will manifestly be satisfied by supposing Hence Ap + 29 Ap + 3 , & c . ... each = 0 . = We then have 1 = ( p + 1 ) Ap + 1 ; 1 .. Ap + 1 p + 1 A , A 2 + + ... + np N 1 + 2 + ... + n p + 1 and therefore limit 1 +2 + ... tr N2 + ...
Side 35
... equation a cos A atan A - tan ( tan 4 ( sin A sin A cos A + B ( a + b ) tan 9 A + B 2 + B ) A + B btan tan B 2 A + B A + B cos A sin 2 2 b cos B ( sin A ÷ B cos B مار 2 A COS 2 + B sin B ) . D2 But by ( 4 ) , A + B A TRIGONOMETRY . 35.
... equation a cos A atan A - tan ( tan 4 ( sin A sin A cos A + B ( a + b ) tan 9 A + B 2 + B ) A + B btan tan B 2 A + B A + B cos A sin 2 2 b cos B ( sin A ÷ B cos B مار 2 A COS 2 + B sin B ) . D2 But by ( 4 ) , A + B A TRIGONOMETRY . 35.
Side 39
Francis James Jameson. c , c ' are the two roots of the equation b2 = a2 + c2 2ac cos B , G or c2 2ac cos B + a2 b2 = 0 ... equations A + B 2 90 ° 2 A B α b O and tan cot 2 a + b determine 2 ~ + A + B Α B and 2 A + B Α - 2 ; and therefore ...
Francis James Jameson. c , c ' are the two roots of the equation b2 = a2 + c2 2ac cos B , G or c2 2ac cos B + a2 b2 = 0 ... equations A + B 2 90 ° 2 A B α b O and tan cot 2 a + b determine 2 ~ + A + B Α B and 2 A + B Α - 2 ; and therefore ...
Side 56
... equation P = Mf is true , where f expresses the accelerating effect of a force whose statical measure is P. ( B ) . A body weighing 10 lbs . is moved by a constant force which generates in a second a velocity of 1 foot per second ; find ...
... equation P = Mf is true , where f expresses the accelerating effect of a force whose statical measure is P. ( B ) . A body weighing 10 lbs . is moved by a constant force which generates in a second a velocity of 1 foot per second ; find ...
Side 57
... equation P = Mf , or moving force the product of mass into accelerating force . The question is simply this : Given the mass of body and the accelerating force , find the moving force . Let M be mass , ƒ accelerating force . Therefore ...
... equation P = Mf , or moving force the product of mass into accelerating force . The question is simply this : Given the mass of body and the accelerating force , find the moving force . Let M be mass , ƒ accelerating force . Therefore ...
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The Principles of the Solution of the Senate-House 'Riders: Exemplified by ... Francis J. Jameson Ingen forhåndsvisning - 2018 |
The Principles of the Solution of the Senate-House 'Riders: Exemplified by ... Francis J. Jameson Ingen forhåndsvisning - 2015 |
Almindelige termer og sætninger
AC² AN.NM Arithmetic arithmetical progression axis bisects body C₁ Cambridge centre of gravity chord CHURCHILL BABINGTON circle cloth cone Conic Sections conjugate hyperbola constant curvature curve cycloid describe diameter direction directrix distance drawn Edition ellipse equations equilibrium Fellow of St fluid focus geometrical given point Hence horizontal hyperbola inches inclined inscribed John's College joining latus-rectum least common multiple Lemma length locus meet mirror move number of seconds oscillation parabola parallel parallelogram particle perpendicular plane polygon pressure prop proportional proposition prove pullies quadrilateral quantity radius ratio rays rectangle refraction right angles sewed shew sides specific gravity spherical square straight line string surface tan² tangent triangle ABC Trinity College tube V₁ vary vertex vertical W₁ weight
Populære passager
Side 4 - To divide a given straight line into two parts, so that the rectangle contained by the whole and one of the parts, shall be equal to the square of the other part.
Side 6 - The angle at the centre of a circle is double of the angle at the circumference upon the same base, that is, upon the same part of the circumference.
Side 11 - AB is a diameter, and P any point in the circumference of a circle; AP and BP are joined and produced if necessary ; if from any point C of AB, a perpendicular be drawn to AB meeting AP and .BP in points D and E respectively, and the circumference of the circle in a point F, shew that CD is a third proportional of CE and CF.
Side 9 - IF the angle of a triangle be divided into two equal angles, by a straight line which also cuts the base; the segments of the base shall have the same ratio which the other sides of the triangle have to one another...
Side 4 - In any right-angled triangle, the square which is described upon the side subtending the right angle, is equal to the squares described upon the sides which contain the right angle.