 FK : in the same manner it may be demonstrated, that FL, FM, FG are each of them equal to FH, or FK : therefore the five straight lines FG, FH, FK, FL, FM are equal to one another : wherefore the circle described from the centre F, at the distance of...  Euclid's Elements of Geometry: The First Six, the Eleventh and Twelfth Books - Side 183af Euclid - 1765 - 464 siderFuld visning - Om denne bog
 | John Keill - 1723 - 444 sider
...Perpendicular F K. In the fame Manner we demonstrate, that FL, FM,- or FG, is equal to FH, or F K. Therefore the five Right Lines FG, FH, FK, FL, FM, are equal to each other. And fo a Circle defcribed on the Center F, with either of the Diftances FG, FH, FK, FL,... | |
 | Euclid, John Keill - 1733 - 444 sider
...Perpendicular FH equal to the Perpendicular F K. In the fame Manner we demonftrate, that FL, FM, or FG, is equal to FH, or FK. Therefore the five Right Lines FG, FH, FK, FL, FM, are equal to each other. And fo a Circle defcribed oh the Center F, with either of the Diftances FG, FH, FK, FL,... | |
 | John Keill - 1772 - 462 sider
...the Perpendicular F K. In the fame manner we demonftrate, that FL, FM, or FG, is equal to FH, or F K. Therefore the five Right • Lines FG, FH, FK, FL, FM, are equal to each other, and fo a Circle defcribed on the Centre F, with either of the Diftances FG, FH, FK, FL,... | |
 | Euclid - 1781 - 552 sider
...perpendicular FH is equal to the perpendicular FK : In the fame manner it may be demonftrated that FL, FM, FG are each of them equal to FH or FK ; therefore the five ftraight lines FG, FH, FK, FL, FM are equal to one another : Wherefore the cifcle defcribed from the... | |
 | Robert Simson - 1781 - 534 sider
...perpendicular FH is equal to the perpendicular FK. in the fwne manner it may be demonftrated that FL, FM, FG are each of them equal to FH or FK; therefore the five ftraight lines FG, FH, FK, FL, FM are equal to one another. wherefore the circle defcribe .'. from... | |
 | Euclid, John Playfair - 1795 - 462 sider
...perpendicular FH is equal to the perpendicular FK : in the fame manner it may be demonftrated, that FL, FM, FG are each of them equal to FH or FK : therefore the five ftraight lines FG, FH, FK, FL, FM are equal to one another : wherefore the circle defcribed from the... | |
 | Robert Simson - 1804 - 530 sider
...perpendicular FH is equal to the perpendicular FK. in the fame manner it may be demonftrated that FL, FM, FG are each of them equal to FH or FK; therefore the five ftraight lines FG, FH, FK, FL, FM are equal to one another, wherefore the circle de~ fcribed from the... | |
 | Euclides - 1816 - 588 sider
...perpendicular FH is equal to the perpendicular FK : In the same manner it may be demonstrated ; that FL, FM, FG are each of them equal to FH, or FK : Therefore the five straight lines FG, FH, FK, FL, FM are equal to one another : Wherefore the circle described from the... | |
 | John Playfair - 1819 - 350 sider
...perpendicular FH is equal to the perpendicular FK : in the same manner it may be demonstrated, that FL, FM, FG are each of them equal to FH or FK , therefore the five straight lines FG, FH, FK, FL, FM are equal to one another : wherefore the circle described from the... | |
 | Peter Nicholson - 1825 - 1046 sider
...perpendicular FH is equal to the perpendicular FK : In the same manner it may be demonstrated, that FL, FM, FG are each of them equal to FH or FK : Therefore the uve straight linei FG, FH, FK , FL, FM are equal to on* another: Wherefore the circb described from... | |
| |
