Library of Useful Knowledge: Geometry plane, solid, and spherical [by Pierce Morton] 1830. Elements of trigonometry, by W. Hopkins. 1833. Elements of spherical trigonometry, by A. De Morgan. A treatise on algebraical geometry, by S.W. Waud. 1835Baldwin & Craddock, 1835 |
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Resultater 1-5 af 49
Side 13
... rallel to C D. C E H B D right angles to EF , it will be at right For , if the straight line G H be at angles to A B , because A B is parallel to EF ( 14. ) : and , for the like reason , it will be at right angles to CD : there- fore ...
... rallel to C D. C E H B D right angles to EF , it will be at right For , if the straight line G H be at angles to A B , because A B is parallel to EF ( 14. ) : and , for the like reason , it will be at right angles to CD : there- fore ...
Side 15
... rallel . E Let the straight lines AD , BC be equal and parallel , and let them be join- ed towards the same parts by A B , CD : AB shall be both equal to CD , and parallel to it . Join B D. Then , because in the tri- angles ADB , CBD ...
... rallel . E Let the straight lines AD , BC be equal and parallel , and let them be join- ed towards the same parts by A B , CD : AB shall be both equal to CD , and parallel to it . Join B D. Then , because in the tri- angles ADB , CBD ...
Side 16
... rallel to B C. And , for the like reason , A B is parallel to CD . Therefore , in each of the three cases , the figure is a parallelogram . Therefore , & c . Cor . 1. ( Euc . i . 34. second part of . ) A parallelogram is bisected by ...
... rallel to B C. And , for the like reason , A B is parallel to CD . Therefore , in each of the three cases , the figure is a parallelogram . Therefore , & c . Cor . 1. ( Euc . i . 34. second part of . ) A parallelogram is bisected by ...
Side 17
... rallel to A C , and let it meet the base B C produced in E , and join A E. Then , because D E is parallel to A C , the triangle A C D is ( 27. ) equal to ACE . Therefore , the triangles ABC , ACD , together , are equal to the triangles ...
... rallel to A C , and let it meet the base B C produced in E , and join A E. Then , because D E is parallel to A C , the triangle A C D is ( 27. ) equal to ACE . Therefore , the triangles ABC , ACD , together , are equal to the triangles ...
Side 28
... rallel to the sides of the triangle CAB , which has its angles at A and B , and therefore at C , equal to the given angles ( 18. ) . Again , because ca is parallel to CA , the angle acA is equal ( 15. ) to the alternate angle CA c ...
... rallel to the sides of the triangle CAB , which has its angles at A and B , and therefore at C , equal to the given angles ( 18. ) . Again , because ca is parallel to CA , the angle acA is equal ( 15. ) to the alternate angle CA c ...
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A B C ABCD adjacent angles altitude apothem base BC bisect centre chord circum circumference circumscribed coincide common measure common section compounded cone conic section contained convex surface cylinder describe a circle diameter dihedral angle divided draw drawn edges equal angles equimultiples ference fore four magnitudes frustum given point given straight line gles harmonical harmonical mean Hence hyperbola hypotenuse inscribed join likewise locus meet parallel parallelogram parallelopiped pass pendicular pentagon perimeter perpendicular plane prism Prob produced PROP proposition pyramid quadrilateral radii radius rallel rectangle rectilineal figure regular polygon respectively right angles Scholium scribed segment sides A B similar solid angles sphere spherical angle square of A B straight lines A B tangent third three sides touch triangle ABC vertex vertical