The Elements of Euclid: Viz. the First Six Books, Together with the Eleventh and Twelfth ... Also the Book of Euclid's Data, in Like Manner CorrectedWingrave and Collingwood, 1816 - 528 sider |
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Resultater 1-5 af 89
Side 9
... base BC shall coincide with the base EF , because the point B coinciding with E , and C with F , if the base BC does not coincide with the base EF , two straight lines would inclose a space , which is impossible . Therefore the base ...
... base BC shall coincide with the base EF , because the point B coinciding with E , and C with F , if the base BC does not coincide with the base EF , two straight lines would inclose a space , which is impossible . Therefore the base ...
Side 11
... BC common to both the two sides , DB , BC are equal to the two AC , CB each to each ; and the angle DBC is equal to the angle ACB ; therefore the base DC is equal to the base AB , and the triangle DBC is equal to the tri- angleb ACB ...
... BC common to both the two sides , DB , BC are equal to the two AC , CB each to each ; and the angle DBC is equal to the angle ACB ; therefore the base DC is equal to the base AB , and the triangle DBC is equal to the tri- angleb ACB ...
Side 12
... base CD are 5. 1. equal to one another : but the an- gle ECD is greater than the angle BCD : wherefore the angle FDC is likewise greater than BCD ; much more then is the ... BC is equal to EF . Therefore BC coinciding with 12 THE ELEMENTS.
... base CD are 5. 1. equal to one another : but the an- gle ECD is greater than the angle BCD : wherefore the angle FDC is likewise greater than BCD ; much more then is the ... BC is equal to EF . Therefore BC coinciding with 12 THE ELEMENTS.
Side 13
... BC is equal to EF . Therefore BC coinciding with EF ; BOOK I. BA and AC shall coincide with ED and DF ; for , if the base BC coincides with the base EF ; but the sides BA , CA do not coincide with the sides ED , FD , but have a differ ...
... BC is equal to EF . Therefore BC coinciding with EF ; BOOK I. BA and AC shall coincide with ED and DF ; for , if the base BC coincides with the base EF ; but the sides BA , CA do not coincide with the sides ED , FD , but have a differ ...
Side 14
... BC , CD , each to each ; and the angle ACD is equal to the angle BCD ; therefore the base AD is equal 4. 1. to the base DB , and the straight line AB is divided into two equal parts in the point D. Which was to be done . A : See N. 3. 1 ...
... BC , CD , each to each ; and the angle ACD is equal to the angle BCD ; therefore the base AD is equal 4. 1. to the base DB , and the straight line AB is divided into two equal parts in the point D. Which was to be done . A : See N. 3. 1 ...
Almindelige termer og sætninger
ABC is given ABCD AC is equal altitude angle ABC angle BAC base BC bisected Book XI centre circle ABC circumference common logarithm cone cylinder demonstrated described diameter draw drawn equal angles equiangular equimultiples Euclid excess fore given angle given in magnitude given in position given in species given magnitude given point given ratio given straight line gnomon greater join less Let ABC logarithm multiple opposite parallel parallelogram AC perpendicular point F polygon prism proportionals proposition Q.E.D. PROP radius ratio of AE rectangle CB rectangle contained rectilineal figure remaining angle right angles segment sides BA similar sine solid angle solid parallelopipeds square of BC straight line AB straight line BC tangent THEOR third triangle ABC vertex wherefore
Populære passager
Side 41 - If a straight line be divided into any two parts, the square of the whole line is equal to the squares of the two parts, together with twice the rectangle contained by the parts.
Side 180 - Wherefore, in equal circles &c. QED PROPOSITION B. THEOREM If the vertical angle of a triangle be bisected by a straight line which likewise cuts the base, the rectangle contained by the sides of the triangle is equal to the rectangle contained by the segments of the base, together with the square on the straight line which bisects the angle.
Side 166 - Equiangular parallelograms have to one another the ratio which is compounded of the ratios of their sides. Let AC, CF be equiangular parallelograms having the angle BCD equal to the angle ECG ; the ratio of the parallelogram AC to the parallelogram CF is the same with the ratio which is compounded •f the ratios of their sides. DH Let BC, CG be placed in a straight line ; therefore DC and CE are also in a straight line (14.
Side 2 - A rhomboid, is that which has its opposite sides equal to one another, but all its sides are not equal, nor its angles right angles.
Side 105 - The first of four magnitudes is said to have the same ratio to the second, which the third has to the fourth, when any equimultiples whatsoever of the first and third being taken, and any equimultiples whatsoever of the second and fourth ; if the multiple of the first be less than that of the second, the multiple of the third is also less than that of the fourth...
Side 79 - The angle in a semicircle is a right angle; the angle in a segment greater than a semicircle is less than a right angle; and the angle in a segment less than a semicircle is greater than a right angle.
Side 1 - A straight line is that which lies evenly between its extreme points.
Side 149 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Side 23 - That, if a straight line falling on two straight lines make the interior angles on the same side less than two right angles, the two straight lines, if produced indefinitely, meet on that side on which are the angles less than the two right angles.
Side 83 - Wherefore from the given circle ABC has been cut off the segment BAC, containing an angle equal to the given angle DQEP PROP. XXXV. THEOR. If two straight lines within a circle cut one another, the rectangle contained by the segments of one of them is equal to the rectangle contained by the segments of the other. Let the...