Geometrical Problems Deducible from the First Six Books of Euclid, Arranged and Solved: To which is Added an Appendix Containing the Elements of Plane Trigonometry ...J. Smith, 1819 - 377 sider |
Fra bogen
Resultater 6-10 af 100
Side 42
... Let the two equal circles cut each other in A and B , and with the centre A ... ABC is an angle A B F in each of the two equal circles , the circumference ... Let the two equal circles ADB , ACB cut each other in A and B ; join AB , and ...
... Let the two equal circles cut each other in A and B , and with the centre A ... ABC is an angle A B F in each of the two equal circles , the circumference ... Let the two equal circles ADB , ACB cut each other in A and B ; join AB , and ...
Side 44
... Let the two circles ACD , ECB touch each other in C , and let ABC , DEC be any two lines drawn through the point of contact . Draw the tangent FCG , and join AD , EB . F BA C E G Then ( Eucl . iii . 32. ) the angle ADC ( FCA = ) BEC ...
... Let the two circles ACD , ECB touch each other in C , and let ABC , DEC be any two lines drawn through the point of contact . Draw the tangent FCG , and join AD , EB . F BA C E G Then ( Eucl . iii . 32. ) the angle ADC ( FCA = ) BEC ...
Side 46
... Let ABC , DCE be two circles which touch each other externally in C , and let AFE be the line joining their centres and produced to the circumferences in A and E. Bisect AE in F , and with the centre Fand any radius , let a circle GHK ...
... Let ABC , DCE be two circles which touch each other externally in C , and let AFE be the line joining their centres and produced to the circumferences in A and E. Bisect AE in F , and with the centre Fand any radius , let a circle GHK ...
Side 47
... Let the two circles ABC , DEC touch each other internally in C , from which let any lines CA , CB be drawn ; and taking any two points G and F , through E and B draw GEI , FBI , and through D and A draw GDH , FAH ; if those lines E B H ...
... Let the two circles ABC , DEC touch each other internally in C , from which let any lines CA , CB be drawn ; and taking any two points G and F , through E and B draw GEI , FBI , and through D and A draw GDH , FAH ; if those lines E B H ...
Side 63
... Let P be the given point within the circle ABC . Find the centre , join OP and produce it to the circumference . From P draw PB at right angles to OA ; it is the line required . Join OB , and on it as a diameter describe a circle OPB ...
... Let P be the given point within the circle ABC . Find the centre , join OP and produce it to the circumference . From P draw PB at right angles to OA ; it is the line required . Join OB , and on it as a diameter describe a circle OPB ...
Indhold
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Andre udgaver - Se alle
Almindelige termer og sætninger
ABCD angle ABC angles at F base centre chord circle ABC circles cut circles touch circumference describe a circle divided draw a line draw the diameter drawn parallel duplicate ratio equal angles equiangular Eucl extremities G draw given angle given circle given in position given line given point given ratio given square given straight line given triangle intercepted isosceles triangle Join AE Join BD Let AB Let ABC let fall line given line joining line required lines be drawn lines drawn mean proportional opposite side parallel to BC parallelogram pendicular point of bisection point of contact point of intersection point required radius rectangle right angles segments semicircle shewn tangent touching the circle trapezium triangle ABC
Populære passager
Side 14 - IF a straight line be divided into two equal, and also into two unequal parts ; the squares of the two unequal parts are together double of the square of half the line, and of the square of the line between the points of section.
Side xiii - IF from any point without a circle two straight lines be drawn, one of which cuts the circle, and the other touches it ; the rectangle contained by the whole line which cuts the circle, and the part of it without the circle,. shall be equal to the square of the line which touches it.
Side 230 - To describe an isosceles triangle, having each of the angles at the base double of the third angle.
Side 327 - The circumference of every circle is supposed to be divided into 360 equal parts, called degrees ; each degree into 60 equal parts, called minutes ; and each minute into 60 equal parts, called seconds.
Side 158 - Iff a straight line be divided into any two parts, four times the rectangle contained by the whole line, and one of the parts, together with the square of the other...
Side 212 - FC are equal to one another : wherefore the circle described from the centre F, at the distance of one of them, will pass through the extremities of the other two, and be described about the triangle ABC.
Side 123 - If from a point, without a parallelogram, there be drawn two straight lines to the extremities of the two opposite sides, between which, when produced, the point does not lie, the difference of the triangles thus formed is equal to half the parallelogram. Ex. 2. The two triangles, formed by drawing straight lines from any point within a parallelogram to the extremities of its opposite sides, are together half of the parallelogram.
Side 305 - Given the vertical angle, the difference of the two sides containing it, and the difference of the segments of the base made by a perpendicular from the vertex ; construct the triangle.
Side 247 - The perpendicular from the vertex on the base of an equilateral triangle is equal to the side of an equilateral triangle inscribed in a circle, whose diameter is the base.
Side 299 - AB be equal to the given bisecting line ; and upon it describe a segment of a circle containing an angle equal to the given angle.