The Elements of Euclid: Also the Book of Euclid's Data ...cor. viz. The first six books, together with the eleventh and twelfthF. Wingrave, 1804 |
Fra bogen
Resultater 6-10 af 73
Side 48
... rectangle contained by the whole line . thus produced , and the part of it produced , together with the fquare of half of the line bisected , is equal to the fquare of the ftraight line which is made up of the half and the part produced ...
... rectangle contained by the whole line . thus produced , and the part of it produced , together with the fquare of half of the line bisected , is equal to the fquare of the ftraight line which is made up of the half and the part produced ...
Side 49
... rectangle AB , BC is double of AK , for BK is equal to BC . therefore the gnomon AKF together with the fquare CK is equal to twice the rectangle AB , BC . to D each of these equals add HF , which is C C B K c . Cor . 4. 26 F E equal to ...
... rectangle AB , BC is double of AK , for BK is equal to BC . therefore the gnomon AKF together with the fquare CK is equal to twice the rectangle AB , BC . to D each of these equals add HF , which is C C B K c . Cor . 4. 26 F E equal to ...
Side 50
... rectangle CK is equal to BN , and GR to RN . but CK is equal to RN , because they are the complements of the parallelogram CO ; therefore alfo BN is equal to GR . and the four rectangles BN , CK , GR , RN , are therefore equal to one ...
... rectangle CK is equal to BN , and GR to RN . but CK is equal to RN , because they are the complements of the parallelogram CO ; therefore alfo BN is equal to GR . and the four rectangles BN , CK , GR , RN , are therefore equal to one ...
Side 54
... rectangle AB , BH is equal to the fquare of AH . with F e G HB Because the ftraight line AC is bifected in E , and produced to the point F , the rectangle CF , FA , together with the square of AE , is equal to the square of EF . but EF ...
... rectangle AB , BH is equal to the fquare of AH . with F e G HB Because the ftraight line AC is bifected in E , and produced to the point F , the rectangle CF , FA , together with the square of AE , is equal to the square of EF . but EF ...
Side 55
... rectangle BC , CD . Book II . 2. 12. I A b . 4. 20 Because the straight line BD is divided into two parts in the point C , the fquare of BD is equal b to the fquares of BC , CD , and twice the rectangle BC , CD . to each of thefe equals ...
... rectangle BC , CD . Book II . 2. 12. I A b . 4. 20 Because the straight line BD is divided into two parts in the point C , the fquare of BD is equal b to the fquares of BC , CD , and twice the rectangle BC , CD . to each of thefe equals ...
Almindelige termer og sætninger
alfo alſo angle ABC angle BAC bafe baſe BC is equal BC is given becauſe the angle becauſe the ratio bifected Book XI cafe circle ABCD circumference cone conſtruction cylinder defcribed demonſtrated drawn EFGH equal angles equiangular equimultiples Euclid excefs faid fame multiple fame ratio fecond fegment fhall fhewn fides fides BA fimilar fince firft firſt folid angle fore fquare fquare of AC given angle given in fpecies given in magnitude given in pofition given magnitude given ratio given ſtraight line gnomon greater join lefs leſs likewife line BC muſt oppofite parallel parallelepipeds parallelogram perpendicular plane angles PROP Propofition pyramid rectangle contained rectilineal figure right angles ſame ſhall ſpace ſphere ſquare ſtraight line AB THEOR theſe thro tiple triangle ABC wherefore
Populære passager
Side 157 - D ; wherefore the remaining angle at C is equal to the remaining angle at F ; Therefore the triangle ABC is equiangular to the triangle DEF. Next, let each of the angles at C, F be not less than a right angle ; the triangle ABC is also, in this case, equiangular to the triangle DEF.
Side 24 - ... be equal, each to each ; and also the third angle of the one to the third angle of the other. Let ABC, DEF be two triangles which have the angles ABC, ECA equal to the angles DEF, EFD, viz.
Side 45 - If a straight line be divided into any two parts, the rectangle contained by the whole and one of the parts, is equal to the rectangle contained by the two parts, together with the square of the aforesaid part.
Side 73 - THE straight line drawn at right angles to the diameter of a circle, from the extremity of...
Side 163 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Side 81 - ELF. Join BC, EF ; and because the circles ABC, DEF are equal, the straight lines drawn from their centres are equal: therefore the two sides BG, GC, are equal to the two EH, HF ; and the angle at G is equal to the angle at H ; therefore the base BC is equal (4.
Side 323 - Equiangular parallelograms have to one another the ratio which is compounded of the ratios of their sides.
Side 80 - EA : and because AD is equal to DC, and DE common to the triangles ADE, CDE, the two sides AD, DE are equal to the two CD, DE, each to each ; and the angle ADE is equal to the angle CDE, for each of them is a right angle ; therefore the base AE is equal (4.
Side 36 - To a given straight line to apply a parallelogram, which shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle.