 | Robert Potts - 1865 - 528 sider
...given straight line. 184. Given the vertical angle, the difference of the two sides containing it, and the difference of the segments of the base made by a perpendicular from the vertex : construct the triangle. 185. Given the vertical angle, and the lengths of two lines drawn from the... | |
 | Robert Potts - 1868 - 434 sider
...given straight line. 130. Given the vertical angle, the difference of the two sides containing it, and the difference of the segments of the base made by a perpendicular from the vertex ; construct the triangle. 131. Given the vertical angle, and the lengths of two lines drawn from the... | |
 | William Thomas Read - 1869 - 176 sider
...the base, or longest side, is to the sum of the other two sides, so is the difference of those sides, to the difference of the segments of the base, made by a perpendicular drawn from the opposite angle. Then the half difference added to half the base, gives the segment adjacent... | |
 | Charles Watkins Merrifield - 1873 - 120 sider
...8 1 in. Ans. Again: 251^ @ 2s. 6d = 7546^. = £& 8í. 10|</. Ans. 2. If AB = 28, BC = 45, CA = 53, the difference of the segments of the base made by a perpendicular from A on BC = (CA + AB)(CA-AB)-7-BC = 81 x 254-45 = 45 = BC ; Л ABC is a right angle, and the area = £(45... | |
 | Edward Atkins - 1874 - 428 sider
...base is a circle. 31. Given the vertical angle, the difference of the two sides containing it, and the difference of the segments of the base made by a perpendicular from the vertex, to construct the triangle. 32. Show that the locus of the middle point of a straight line, which moves... | |
 | Euclid, James Bryce, David Munn (F.R.S.E.) - 1874 - 236 sider
...the difference of the squares on the sides of a triangle is equal to the difference of the squares on the segments of the base, made by a perpendicular from the vertex (I. 37, cor. 3), it follows from Cor. 1 to this Proposition, that the rectangle under the sum and difference... | |
 | Robert Potts - 1876 - 446 sider
...given straight line. 130. Given the vertical angle, the difference of the two sides containing it, and the difference of the segments of the base made by a perpendicular from the vertex ; construct the triangle. 131. Given the vertical angle, and the lengths of two lines drawn from the... | |
 | Edward Atkins - 1876 - 130 sider
...figures. 20. The base of a triangle is 63 ft., and the sides 25 ft. and 52 ft. respectively. Show that the segments of the base, made by a perpendicular from the vertex, are 15 ft. and 48 ft. respectively, and that the area of the triangle is 630 sq. ft. 21. In the same... | |
 | William Frothingham Bradbury - 1877 - 262 sider
...angle to the opposite side, and the perpendicular given, to construct the triangle. 124. Two sides and the difference of the segments of the base made by a perpendicular from the vertical angle to the base given, to construct the triangle. Is there any ambiguity in this Problem... | |
 | George Albert Wentworth - 1879 - 196 sider
...produced: EA C is the A. Ex. 46. Given the vertical angle, the difference of the sides containing it, and the difference of the segments of the base made by a perpendicular from the vertex: construct the triangle. Take AB = difference of base segments; make £ABC — | given Z, and draw AC... | |
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Given the vertical angle, the difference of the two sides containing it, and the difference of the segments of the base made by a perpendicular from the vertex ; construct the triangle. 
