| George Bruce Halsted - 1886 - 394 sider
...in A, rectangle + AG* = GF* = GH* = AH* + AG*, by 243 J 112 PROBLEM II. 313. To divide a given sect **into two parts so that the rectangle contained by the whole and one of the parts** shall be equal to the square on the other part. Jf X GIVEN, the sect AB. REQUIRED, to find a point... | |
| Dalhousie University - 1887 - 206 sider
...the line between the points of section, is equal to the square on half the line. 10. Divide a given **straight line into two parts, so that the rectangle...parts may be equal to the square on the other part.** 11. Tf a straight line touch a circle, and from the point of contact a straight line be drawn at right... | |
| Bedford College - 1888 - 240 sider
...— AE LEE. 1. Prove that the perpendicular bisectors of the sides of a triangle meet at a point. 2. **Divide a straight line into two parts, so that the rectangle contained by the whole and one** part shall be equal to the square on the other part. 3. Describe a circle to pass through three given... | |
| 1888 - 694 sider
...the third digit is twice the sum of the other two. Find the number. 5. Divide a line 20 inches long **into two parts so that the rectangle contained by the whole and one** part may be equal to the square of the other part. 6. Solve xs -f- ys = i8xy. x + y = 12. 7. The hypothenuse... | |
| Canada. Department of the Interior - 1888 - 756 sider
...squares on the two parts, together with twice the rectangle contained by the parts. 7. Divide a ;ivon **straight line into two parts, so that the rectangle contained by the whole** an<l one of the parts shall be equal to the square on the other part. 8. Describe a square that shall... | |
| New Brunswick. Board of Education - 1889 - 1006 sider
...sides of it, prove that the angle contained by these two sides is a right angle. -">. Divide a given **straight line into two parts, so that the rectangle contained by the whole and one of the parts** shall !«• i-qual to the square of the other part. Female Candidates for Class I will omit the 1st... | |
| E. J. Brooksmith - 1889 - 354 sider
...shall be equal to the rectangle contained by the sum and difference of two given straight lines. 5. **Divide a straight line into two parts so that the rectangle contained by the whole** line and one of the parts shall be equal to the square of the other part. If AB be divided in C so... | |
| Edward Albert Bowser - 1890 - 414 sider
...triangles OAB, OBC, OCA are equal. 59. Construct a square that shall be one-third of a given square. 60. **Divide a straight line into two parts so that the rectangle contained by the whole and one** part may be equal to a given square. 61. Produce AB to C so that the rectangle of AB and AC may be... | |
| Edward Mann Langley, W. Seys Phillips - 1890 - 538 sider
...complements, show that the complement is equal to half the other parallelogram. Ex. 652. — Divide a given **straight line into two parts so that the rectangle contained by the whole and one** part may be equal to the rectangle contained by the other part and a given finite straight line. Ex.... | |
| Euclid - 1890 - 442 sider
...sq. on AX + sq. on BX = 2 (sq. on AM + sq. on MX). 95 Proposition 11. PROBLEM — To divide a given **straight line into two parts so that the rectangle contained by the whole and one** part may be equal to the square on the other part. Let AB be the given st. line. On AB describe the... | |
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