 | George Bruce Halsted - 1886 - 394 sider
...in A, rectangle + AG* = GF* = GH* = AH* + AG*, by 243 J 112 PROBLEM II. 313. To divide a given sect into two parts so that the rectangle contained by the whole and one of the parts shall be equal to the square on the other part. Jf X GIVEN, the sect AB. REQUIRED, to find a point... | |
 | Dalhousie University - 1887 - 206 sider
...the line between the points of section, is equal to the square on half the line. 10. Divide a given straight line into two parts, so that the rectangle...parts may be equal to the square on the other part. 11. Tf a straight line touch a circle, and from the point of contact a straight line be drawn at right... | |
 | Bedford College - 1888 - 240 sider
...— AE LEE. 1. Prove that the perpendicular bisectors of the sides of a triangle meet at a point. 2. Divide a straight line into two parts, so that the rectangle contained by the whole and one part shall be equal to the square on the other part. 3. Describe a circle to pass through three given... | |
 | 1888 - 686 sider
...the third digit is twice the sum of the other two. Find the number. 5. Divide a line 20 inches long into two parts so that the rectangle contained by the whole and one part may be equal to the square of the other part. 6. Solve xs -f- ys = i8xy. x + y = 12. 7. The hypothenuse... | |
 | Canada. Department of the Interior - 1888 - 756 sider
...squares on the two parts, together with twice the rectangle contained by the parts. 7. Divide a ;ivon straight line into two parts, so that the rectangle contained by the whole an<l one of the parts shall be equal to the square on the other part. 8. Describe a square that shall... | |
 | New Brunswick. Board of Education - 1889 - 1004 sider
...sides of it, prove that the angle contained by these two sides is a right angle. -">. Divide a given straight line into two parts, so that the rectangle contained by the whole and one of the parts shall !«• i-qual to the square of the other part. Female Candidates for Class I will omit the 1st... | |
 | E. J. Brooksmith - 1889 - 356 sider
...shall be equal to the rectangle contained by the sum and difference of two given straight lines. 5. Divide a straight line into two parts so that the rectangle contained by the whole line and one of the parts shall be equal to the square of the other part. If AB be divided in C so... | |
 | Edward Albert Bowser - 1890 - 414 sider
...triangles OAB, OBC, OCA are equal. 59. Construct a square that shall be one-third of a given square. 60. Divide a straight line into two parts so that the rectangle contained by the whole and one part may be equal to a given square. 61. Produce AB to C so that the rectangle of AB and AC may be... | |
 | Edward Mann Langley, W. Seys Phillips - 1890 - 538 sider
...complements, show that the complement is equal to half the other parallelogram. Ex. 652. — Divide a given straight line into two parts so that the rectangle contained by the whole and one part may be equal to the rectangle contained by the other part and a given finite straight line. Ex.... | |
 | Euclid - 1890 - 442 sider
...sq. on AX + sq. on BX = 2 (sq. on AM + sq. on MX). 95 Proposition 11. PROBLEM — To divide a given straight line into two parts so that the rectangle contained by the whole and one part may be equal to the square on the other part. Let AB be the given st. line. On AB describe the... | |
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AB be the given straight line ; it is required to divide it into two parts, so that the rectangle contained by the whole, and one of the parts, shall be equal to the square of the other part. 
