 | Euclides - 1853 - 176 sider
...С d. Wherefore, if a straight line, &c. QED PROPOSITION XI. — PROBLEM. To divide a given straigM line into two parts, so that the rectangle contained by the whole and one of the parts shall be equal to the square of the other part. LET ab be the given straight line ; it is required... | |
 | William Walton, Charles Frederick Mackenzie - 1854 - 266 sider
...diameter, the difference of the parallelograms is equal to twice the triangle BSD. 2. Divide a given straight line into two parts so that the rectangle contained by the whole line and one of the parts shall be equal to the square of the other part. Produce a given straight... | |
 | Cambridge univ, exam. papers - 1854 - 282 sider
...therefore the difference of the parallelograms GF, EH is equal to twice the triangle KBD. 2. Divide a given straight line into two parts so that the rectangle contained by the whole line and one of the parts shall be equal to the square of the other part. Produce a given straight... | |
 | G. Ainsworth - 1854 - 216 sider
...— - = -- (-4, and solving, x=lo. 3. Divide the number 20 into two such parts, that the product of the whole and one of the parts may be equal to the square of the other part. Let 2ж=; the difference of the two parts. Now, 20 being the sum, 10 + ж= the greater... | |
 | William Somerville Orr - 1854 - 532 sider
...the remarks at the end of this book. PROPOSITION XI.— PROBLEM. To divide a given straight line (AB) into two parts, so that the rectangle contained by the whole, and от of the parts, shall be equal to the square of the other part. From A draw AC perpendicular and... | |
 | Great Britain. Committee on Education - 1855 - 976 sider
...described upon the other two sides of it, the angle contained by those two sides is a right angle. 3. Divide a straight line into two parts, so that the...rectangle contained by the whole and one of the parts shall be equal to the square of the other part. Section 3. 1. The angles in the same segment of a circle... | |
 | Robert Potts - 1855 - 1050 sider
...divides them into two equal parts. Prove also that the two diameters bisect each other. 3. Divide a given straight line into two parts, so that the rectangle contained by the whole, and one of the parts, shall be equal to the square of the other part Solve the same problem algebraically, and give the geometrical... | |
 | Euclides - 1855 - 262 sider
...equal to the square oflhe other part. Let AB be the given straight line. It is required to divide AB into two parts, so that the rectangle contained by the whole and one of tLe parts, shall be equal to the square of the other part. Upon AB describe (I. 46) the square СB.... | |
 | Cambridge univ, exam. papers - 1856 - 252 sider
...contained by the whole and that part, together with the square of the other part. 8. Divide a given straight line into two parts, so that the rectangle contained by the whole, and one of the parts, shall be equal to the square of the other part. 9. If a straight line drawn through the centre of a... | |
 | Henry White - 1856 - 178 sider
...another upon one side of it are either two right angles, or are together equal to two right angles. 18 Divide a straight line into two parts, so that the rectangle contained by the whole and ono of the parts shall be equal to the square of the other part. 19 If two circles cut each other,... | |
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AB be the given straight line ; it is required to divide it into two parts, so that the rectangle contained by the whole, and one of the parts, shall be equal to the square of the other part. 
