| Euclides - 1853 - 176 sider
...С d. Wherefore, if a straight line, &c. QED PROPOSITION XI. — PROBLEM. To divide a given straigM **line into two parts, so that the rectangle contained by the whole and one of the parts** shall be equal to the square of the other part. LET ab be the given straight line ; it is required... | |
| William Walton, Charles Frederick Mackenzie - 1854 - 266 sider
...diameter, the difference of the parallelograms is equal to twice the triangle BSD. 2. Divide a given **straight line into two parts so that the rectangle contained by the whole** line and one of the parts shall be equal to the square of the other part. Produce a given straight... | |
| Cambridge univ, exam. papers - 1854 - 282 sider
...therefore the difference of the parallelograms GF, EH is equal to twice the triangle KBD. 2. Divide a given **straight line into two parts so that the rectangle contained by the whole** line and one of the parts shall be equal to the square of the other part. Produce a given straight... | |
| G. Ainsworth - 1854 - 216 sider
...— - = -- (-4, and solving, x=lo. 3. Divide the number 20 into two such parts, that the product of **the whole and one of the parts may be equal to the square** of the other part. Let 2ж=; the difference of the two parts. Now, 20 being the sum, 10 + ж= the greater... | |
| William Somerville Orr - 1854 - 532 sider
...the remarks at the end of this book. PROPOSITION XI.— PROBLEM. To divide a given straight line (AB) **into two parts, so that the rectangle contained by the whole, and** от of the parts, shall be equal to the square of the other part. From A draw AC perpendicular and... | |
| Great Britain. Committee on Education - 1855 - 976 sider
...described upon the other two sides of it, the angle contained by those two sides is a right angle. 3. **Divide a straight line into two parts, so that the...rectangle contained by the whole and one of the parts** shall be equal to the square of the other part. Section 3. 1. The angles in the same segment of a circle... | |
| Robert Potts - 1855 - 1050 sider
...divides them into two equal parts. Prove also that the two diameters bisect each other. 3. Divide a given **straight line into two parts, so that the rectangle contained by the whole, and one of the parts,** shall be equal to the square of the other part Solve the same problem algebraically, and give the geometrical... | |
| Euclides - 1855 - 262 sider
...equal to the square oflhe other part. Let AB be the given straight line. It is required to divide AB **into two parts, so that the rectangle contained by the whole and one of** tLe parts, shall be equal to the square of the other part. Upon AB describe (I. 46) the square СB.... | |
| Cambridge univ, exam. papers - 1856 - 252 sider
...contained by the whole and that part, together with the square of the other part. 8. Divide a given **straight line into two parts, so that the rectangle contained by the whole, and one of the parts,** shall be equal to the square of the other part. 9. If a straight line drawn through the centre of a... | |
| Henry White - 1856 - 178 sider
...another upon one side of it are either two right angles, or are together equal to two right angles. 18 **Divide a straight line into two parts, so that the rectangle contained by the whole and** ono of the parts shall be equal to the square of the other part. 19 If two circles cut each other,... | |
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